Questions · Infrastructure
How is the sum for the days of recording really done?
You turn the bit rate into a volume and multiply by the days. There is one equivalence you need: one megabit per second sustained is about ten point eight gigabytes a day. With that you can do the sums with a pencil and paper.
An example, and it is only an example: twenty-four cameras at an average of four megabits per second is ninety-six megabits per second, which at ten point eight gigabytes a day per megabit gives a little over a terabyte a day. Thirty days would be some thirty-one terabytes of video. On top of that you have to add what drive redundancy takes and leave free space so the system has room to work, so the actual purchase is a good deal larger than the figure from the sums.
The weak point in all of this is those four megabits. If they come from a datasheet, the calculation is born wrong. They are measured with the cameras installed, on the real scene and at the worst hour, which is at night with movement in front of them.
Where it is set out in full.
All the questions.
Five hundred and forty-four, grouped by topic. Each with its own page.
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See it working.
A written answer is enough to decide whether it interests you. To know whether it works at your site you have to see it on a real scene, with the image as it is and, on top of it, what the system understands from it. That is on the IRIS Neural website, which is the group's product.